Correct.

Diazepam is the correct answer.
Since both have the same pKa, they will both exist 99% in the
non-protonated form at a pH 2 units above their pKa. The non-protonated form is the uncharged form for a base, i.e.: for diazepam.

 

Incorrect.

Diazepam is the correct answer.
Since both have the same pKa, they will both exist 99% in the
non-protonated form at a pH 2 units above their pKa. The non-protonated form is the uncharged form for a base, i.e.: for diazepam.

 

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